Mark the loops with clock wise arrow as the direction of the current flowing.
For the loop 1, You got two individual two loops from the circuit. Statement of Thevenin’s theorem :
After going through the following examples we can better understand the theorem further. The entire active circuit or network is a voltage source of Thevenin Voltage with Thevenin resistance connected in series with it.
Thevenin’s theorem is a direct consequence of the Superposition theorem. This voltage is VTh. VTh = I2.4 volt. Step-5: Place in series with to form the Thevenin's equivalent circuit (replacing the imaginary fencing portion or fixed part of the circuit with an equivalent practical voltage source) as shown in above figure. Once again, calculating this resistance may be a difficult task but one can try to use the standard circuit reduction technique or transformation techniques. Procedure for applying Thevenin's theorem
Notify me of follow-up comments by email. Apply KVL (Kirchhoff’s Voltage Law) and find out loop current. Consider the circuit below. A simple circuit as shown in above figure is considered to illustrate the concept of equivalent circuit and it is always possible to view even a very complicated circuit in terms of much simpler equivalent source and load circuits. CTRL + SPACE for auto-complete. Now appy KVL in each loop. Voltage across the load Step 2: View back into the open circuited network i.e. Prove it! The Thevenin theorem says that any circuit with energy sources and resistors can be converted to a voltage source (Thevenin voltage) and a series resistance (Thevenin resistance). In order to avoid such repeated computation, it is desirable to introduce a method that will not have to be repeated for each value of variable component. Save my name, email, and website in this browser for the next time I comment.
Step-3: Redraw the circuit with each practical source replaced by its internal resistance as shown in figure.
Subsequently the reduction of computational complexity that involves in solving the current through a branch for different values of load resistance (R) is also discussed. Calculate the resistance that would exist between the load terminals ( or equivalently one can think as if a voltage source is applied across the load terminals and then trace the current distribution through the circuit in order to calculate the resistance across the load terminals.
Now connect RL = 10 ohm across A and B terminal. Thevenin Theorem tells that an active circuit between two load terminals can be considered as an individual voltage source. To understand Thevenin Theorem let us take a simple example of a resistive active circuit as shown below.Here first we will disconnect the load from the circuit and then measure the voltage across the terminals of the circuit.
It is the open circuit voltage measured at the two terminals of interest with the load impedance ZL removed.
Step 2 :Calculate the open circuit voltage Voc or RTH . You can verify this value of VTh choosing another path in the circuit from terminal A to B.
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